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ayagirl posted: 14 Jul at 11:25 am
amino acid sequences are drawn from N to C terminal..then in you given data, lysine would be the first amino acid then tryptophan would be the last, connections between amino acids are effected through the reaction of the NH2 of one amino acid and COOH group of the other to form an amideplane..thus in your sequence COOH of your lysine will react with NH2 of your valine forming an amide plane..then COOH of valine will react with NH2 of the next one which is threonine….so on….in dealing with charges, the diffent amino acids will have different charges at different pHs..Consult Biochem books for the titration of aminoacids and there you willknow what charges will each amino acid aquire at certian pH..sum all the charges at that pH and that would be the total ionic charge of your amino acid sequence at that pH..
gorgeousgoddess posted: 16 Jul at 3:29 pm
From the above link, you can check the structures of all your amino acids. You will see that for all your amino acids, there is an amino terminal (this is your -NH2) and your carboxylic terminal (-COOH). In peptide bonds, the amino terminal of one amino acid (it becomes =NH3+) is bonded to the carboxylic end of your next amino acid (which becomes -COO-). When you say that lysine is your amino terminal acid, this means that the -NH2 of lysine is free and is not bonded to another amino acid. it is the carboxylic end of lysine that is bonded to the amino terminal of your next amino acid, valine. Then valine’s carboxylic end is connected to the amino end of threonine…so on and so forth…That is why your tryptophan is your carboxy-terminal amino acid because its carboxylic acid side is not bonded.
John Chalinder MT USA GMT -7 posted: 19 Jul at 12:28 am
Check out the following site for well illustrated examples:
rodent posted: 19 Jul at 3:05 am
At pH 7.0, the amino terminal NH2 group and the amino group of lysine side chain will be charged positively and the carboxylic groups in the side chains of aspartic and glutamic acid, as well as the C-terminal COOH-group will be charged negatively, so the overall charge will be -1.
The structural formula (eh… not the best picture) is NH2-C(R1)-C(O)-NH-C(R2)-C(O)(and so on)-NH-C(R10)-COOH, where R1 is the side chain of Lys, R2 the side chain of Val,etc. R10 – the side chain of Trp